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The length of some diagonalization games

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Abstract.

For X a separable metric space and \(\alpha\) an infinite ordinal, consider the following three games of length \(\alpha\): In \(G^{\alpha}_1\) ONE chooses in inning \(\gamma\) an \(\omega\)–cover \(O_{\gamma}\) of X; TWO responds with a \(T_{\gamma}\in O_{\gamma}\). TWO wins if \(\{T_{\gamma}:\gamma<\alpha\}\) is an \(\omega\)–cover of X; ONE wins otherwise. In \(G^{\alpha}_2\) ONE chooses in inning \(\gamma\) a subset \(O_{\gamma}\) of \({\sf C}_p(X)\) which has the zero function \(\underline{0}\) in its closure, and TWO responds with a function \(T_{\gamma}\in O_{\gamma}\). TWO wins if \(\underline{0}\) is in the closure of \(\{T_{\gamma}:\gamma<\alpha\}\); otherwise, ONE wins. In \(G^{\alpha}_3\) ONE chooses in inning \(\gamma\) a dense subset \(O_{\gamma}\) of \({\sf C}_p(X)\), and TWO responds with a \(T_{\gamma}\in O_{\gamma}\). TWO wins if \(\{T_{\gamma}:\gamma<\alpha\}\) is dense in \({\sf C}_p(X)\); otherwise, ONE wins. After a brief survey we prove: 1. If \(\alpha\) is minimal such that TWO has a winning strategy in \(G^{\alpha}_1\), then \(\alpha\) is additively indecomposable (Theorem 4) 2. For \(\alpha\) countable and minimal such that TWO has a winning strategy in \(G^{\alpha}_1\) on X, the following statements are equivalent (Theorem 9): a) TWO has a winning strategy in \(G^{\alpha}_2\) on \({\sf C}_p(X)\). b) TWO has a winning strategy in \(G^{\alpha}_3\) on \({\sf C}_p(X)\). 3. The Continuum Hypothesis implies that there is an uncountable set X of real numbers such that TWO has a winning strategy in \(G^{\omega^2}_1\) on X (Theorem 10).

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Received: 14 February 1997

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Scheepers, M. The length of some diagonalization games. Arch Math Logic 38, 103–122 (1999). https://doi.org/10.1007/s001530050117

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  • DOI: https://doi.org/10.1007/s001530050117

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