Solution to a generalization of the busy Beaver problem

Let ϕ be a fixed numerical function. If the k-state Turing machine M with input string ϕ(k) (that is, started in its initial state scanning the leftmost 1 of a single string of ϕ(k) 1s on an otherwise blank tape) produces the output string m (that is, halts in its halting state scanning the leftmost 1 of a single string of m 1s on an otherwise blank tape), we shall say that the ϕ-fecundity of M is m. If M halts in any other position or state, or fails to halt, its ϕ-fecundity is 0.
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