Imaginary maths over TIME COGNITION Consider an empty space In that a ball is set to evolve Y T Y' T' X' X t= set of variables with identical events corresponds to t A set of event is happening in the space It can be anything such as observing a space/geometries in space etc.. Two set of relative events are occurred and the maximum probable ways of happening the event is consider to evaluate the geometry of the above system Here time is considered to be an independent event from space the assumption is such a way that before and after the event the space is in absolute time singularity so the function of defining time will be the imaginary coordinates X-X'=a ;Probability maximum Y-Y'=b For all possible directions in space we consider a drag towards time The drag in the path a and b a/T'-t' = constant T , where t-t'=T b/T'-t' = a+b/T'-t'= C t t' Imaginary maths over TIME COGNITION The observance is taken as a scalar quantity in such space as the geometry is valid only when the patterns are recognised O-O=C The boundary conditions are constrained to the time factors Such that 0-0/0-0 = O* observance is dependent on time * = now definable eg. Vectors But is not defined in O* infinity O-O = O* O-O*= O O-O=C O-O*=C+0 O*= -C CORRESPONDING DRAG ON C Consider another observer O' who is not defined in any space The observer in the double imagination O' O-O'/O-O' CORRESPONDS T-T'/T-T' T-T'/a+b = O'/a+b O'/C(T'-T') O'/V(T)-V(t) V(T,t) drags corresponds C V'(T,t) = t-t/t-t = O'/a-b O'/V(t)-V(T) THE TOTAL DRAG CORRESPONDS O'/V(T)-V(t) + O'/V(t)-V(T) O' ( (V(t)V(T)) +(V(T)-V(t) / (V(T)V(t)).(V(t)-V(T))) Imaginary maths over TIME COGNITION At present V(t)-V(T) =a* V(T)-V(t) =b* O'(a*+b*/(a-b)(b-a)) = D The constant D is the mode of interaction eg. Light C+D=O-O'/(T-T')(t-t') Assume D >> C THEN O' CORRESPONDS T-T' Relative to O as (a+b)(C+D) (POS).(DRAG) O' CORRESPONDS TO t-t' O'=T-T'/a+b /t-t'/a-b C+D = O – ( T-T'/a+b / t-t'/a-b ) /(T-T')(t-t') O – ( T-T')(a-b) /(t-t')(a+b) / ( T-T') (t-t') O / (T-T') (t-t') – (a-b) / (t-t')*2 (a+b) D>>C SUCH THAT T-T'= at D a-b/ (t-t')*2 (a+b) a+b/T'-T' = C (t-t')*2 = (O-O')/(C+D)(T-T') The initial start in interaction D is defined by ((a-b)/(O-O') / (C+D)D ). (a+b) D/O' = a+b/(a-b)(b-a) D/O'= D* = a+b/(a-b)(b-a) ( (a-b/O-O') / (C+D)(a+b)/(a-b)(b-a) ) (a+b) Imaginary maths over TIME COGNITION In the space CORRESPONDS D O-O'=D O'=O-D O(C(T'-t'))= O-D O(C(T'-t')) = O' O'/O = V(T') – V(t') Thus O* = V(T') – V(t') ( (a-b)/(O'/V(T)-V(t)) – (O'/(V(T') – V(t')) / (C+D) ( (a+b)/(a-b)(b-a))) (a+b) D* over O' ((a-b)/D ) / (C+D)((a+b)/(a-b)(b-a))(a+b) = O (((a-b)/D)/(a+b)(C+D)/(a-b)(b-a))(a+b) =O (a-b)(a-b)(b-a)/(C+D)D = O (a-b)*2(b-a)/ (C+D) = O* ( O/(T-T')(t-t') ) –( (a-b)/ (t-t')*2(a+b)) O'= O-D for D>>C O*/(T-T')(t-t') = a-b/ (t-t')*2(a+b) Equating in the equation ((a-b)*3/(C+D))/((a-b)/(t-t')*2(a+b)) = (a-b)*2/(C+D)(t-t')*2(a+b) = (a-b)*2/ (a+b)(C+D)(T-T') =(a-b)*2/ (a+b)*2(C+D)*2(T-T')(t-t') (C+D)(T-T')(t-t') (C+D)(T-T')(C+D)(t-t') = (X-X')(Y-Y') = b.a (a-b)*2 / (a+b)*2 a*b* at O' when D>>C The assumed boundary condition O-O= C Imaginary maths over TIME COGNITION O* = O' / C(T'-t') O-O'= (C+D)(T-T')(t-t') When D<<C , O=O' When D>>C , O-O = D CORRESPONDS the absolute observance O* Drag ,= (a-b)*2/(a+b)*2 a*b* = D ; C<D (a-b)*2/(a+b)*2 a*b* = C ; C>D Shows the dependency of C and D over O* Y' T Y T' O X' O' X The boundary defined as O-O' = C If T is absolute then The space is real where the same set of events happening in the observed condition satisfying maximum O-O'< E where , E is another interaction greater than C ; E>>D>>C The mirror of space created above generate multiple interactions O = T*(O,O',O'',O'''......) O = O*(a,b,c......n)(O,O',O'',......) / (C,D,E,.....N) In the mirror frame with conditions above O-O' / O-O' = C at T'=T & t=t' (relativity) T'= T-t T= T-t-t' -t-t'=0 t+t'=0 Imaginary maths over TIME COGNITION the initial beginning of event is configured in to zero 0 here the dual observance is accepted since the initial beginning in the mirror frame is zero the final beginning of mirror frame to the another observer O" is back in C here O"= O and E>>D D+E = O-(((T-T')/(a+b))/((t-t')/(a-b))) / (T-T')(t-t') When E>D Then (t-t') = at D with negligible ' C ' O = O'-E In the two dimensions a and b (O'/(V(T')-V(T))) - (O'/(V(t')-V(t))) = E (E/O')/(D/O') E*/D* (O'/(V(T')-V(T)))– (O'/(V(t')-V(t))) / (O'/(V(T)-V(t)))– (O'/(V(T')-V(t'))) = E/D a-b/C-D = E*/D* for the first frame (a-b)*2 (b-a) / D+E = O' E* = D*(( a-b) / (C-D)) O/O' = C+ D / D+E (a-b)*2 / (a+b)*2 ab CORRESPONDS TO O* ; E>D a-b = V(T) a+b = V(t) D+E = V(T)*2 / (V(t)*2)(ab) C+D = V(T')*2 / (V(t')*2)(ab) a-b / C-D = E/D D+E / C+D = ( V(T)V(t')/V(t)V(T'))*2 When O*= -C then D=C ; E=D Then V(T)V(t')/V(t)V(T') = 1 ; the time singularity and M is not defined V(T)V(t')/V(t)V(T')*2 = D(M) ; the spiral symmetry of mass over cognition of D Continues............ Imaginary maths over TIME COGNITION