The backward induction argument for the finite iterated prisoner’s dilemma and the surprise exam paradox

Analysis 57 (3):179–186 (1997)
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Abstract

There are two curious features about the backward induction argument (BIA) to the effect that repeated non-cooperation is the rational solution to the finite iterated prisoner’s dilemma (FIPD). First, however compelling the argument may seem, one remains hesitant either to recommend this solu- tion to players who are about to engage in cooperation or to explain cooperation as a deviation from rational play in real-life FIPD’s. Second, there seems to be a similarity between the BIA for the FIPD and the surprise exam paradox (SEP) and one cannot help but wonder whether the former is indeed no more than an instance of the latter. I argue that there is an important difference between the BIA for the FIPD and the SEP, but that a comparison to the SEP can help us understand why the conclusion of the BIA for the FIPD strikes us as a counterintuitive solution to real-life FIPD’s.

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Author's Profile

Luc Bovens
University of North Carolina, Chapel Hill

References found in this work

Conditionals.Frank Jackson - 1992 - Philosophical Quarterly 42 (167):266.
Conditionals.Frank Jackson - 1988 - Revue Philosophique de la France Et de l'Etranger 178 (3):384-384.
The backward induction paradox.Philip Pettit & Robert Sugden - 1989 - Journal of Philosophy 86 (4):169-182.
The Backward Induction Paradox.Philip Pettit & Robert Sugden - 1989 - Journal of Philosophy 86 (4):169-182.
The paradox of the unexpected examination.Crispin Wright & Aidan Sudbury - 1977 - Australasian Journal of Philosophy 55 (1):41 – 58.

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